0=-16t^2+3016.82t+132000

Solution for 0=-16t^2+3016.82t+132000 equation:

0=-16t^2+3016.82t+132000

We move all terms to the left:

0-(-16t^2+3016.82t+132000)=0

We add all the numbers together, and all the variables

-(-16t^2+3016.82t+132000)=0

We get rid of parentheses

16t^2-3016.82t-132000=0

a = 16; b = -3016.82; c = -132000;
Δ = b2-4ac
Δ = -3016.822-4·16·(-132000)
Δ = 17549202.9124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3016.82)-\sqrt{17549202.9124}}{2*16}=\frac{3016.82-\sqrt{17549202.9124}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3016.82)+\sqrt{17549202.9124}}{2*16}=\frac{3016.82+\sqrt{17549202.9124}}{32}
$